192=3r^2

Solution for 192=3r^2 equation:

192=3r^2

We move all terms to the left:

192-(3r^2)=0

a = -3; b = 0; c = +192;
Δ = b2-4ac
Δ = 02-4·(-3)·192
Δ = 2304
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2304}=48$
$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-48}{2*-3}=\frac{-48}{-6}
=+8
$
$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+48}{2*-3}=\frac{48}{-6}
=-8
$